-4b^2-19b=-4b+10-10b^2

Solution for -4b^2-19b=-4b+10-10b^2 equation:

-4b^2-19b=-4b+10-10b^2

We move all terms to the left:

-4b^2-19b-(-4b+10-10b^2)=0

We get rid of parentheses

-4b^2+10b^2+4b-19b-10=0

We add all the numbers together, and all the variables

6b^2-15b-10=0

a = 6; b = -15; c = -10;
Δ = b2-4ac
Δ = -152-4·6·(-10)
Δ = 465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{465}}{2*6}=\frac{15-\sqrt{465}}{12}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{465}}{2*6}=\frac{15+\sqrt{465}}{12}
$